√3sinxcosx+3cos^2x-3/2=Asin(2x+θ),其中A>0,0

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√3sinxcosx+3cos^2x-3/2=Asin(2x+θ),其中A>0,0√3sinxcosx+3cos^2x-3/2=Asin(2x+θ),其中A>0,0√3sinxcosx+3cos^2x

√3sinxcosx+3cos^2x-3/2=Asin(2x+θ),其中A>0,0
√3sinxcosx+3cos^2x-3/2=Asin(2x+θ),其中A>0,0

√3sinxcosx+3cos^2x-3/2=Asin(2x+θ),其中A>0,0
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√3sinxcosx+3cos^2x-3/2
=(√3/2)·(2sinxcosx)+3/2·(2cos^2x-1)
=(√3/2)·sin2x+3/2·cos2x
=√3[(1/2)·sin2x+(√3/2)·cos2x]
=√3(sin2x·cosπ/3+cos2x·sinπ/3)
=√3sin(2x+π/3)
所以 A=√3,θ=π/3