已知x.y满足(x-1)2+(y+2)2=4,求S=3x-y的最值
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已知x.y满足(x-1)2+(y+2)2=4,求S=3x-y的最值已知x.y满足(x-1)2+(y+2)2=4,求S=3x-y的最值已知x.y满足(x-1)2+(y+2)2=4,求S=3x-y的最值三
已知x.y满足(x-1)2+(y+2)2=4,求S=3x-y的最值
已知x.y满足(x-1)2+(y+2)2=4,求S=3x-y的最值
已知x.y满足(x-1)2+(y+2)2=4,求S=3x-y的最值
三角换元
设x=2(1+cost),y=2(-2+sint)
所以S=6(1+cost)-2(-2+sint)=10+6cost-2sint
=10+√40sin(t+m)
所以MAX=10+2√10
MIN=10-2√10
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