导数A bacteria population is growing at 1000e^-0.2x bacteria per day.If there are initially 2000 bacteria,then how many bacteria will there be after one week.1个细胞每天增加1000e^-0.2x,一周7天,那1个细胞每天就是1000e^-0.2(7),20
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导数A bacteria population is growing at 1000e^-0.2x bacteria per day.If there are initially 2000 bacteria,then how many bacteria will there be after one week.1个细胞每天增加1000e^-0.2x,一周7天,那1个细胞每天就是1000e^-0.2(7),20
导数
A bacteria population is growing at 1000e^-0.2x bacteria per day.If there are
initially 2000 bacteria,then how many bacteria will there be after one week.
1个细胞每天增加1000e^-0.2x,一周7天,那1个细胞每天就是1000e^-0.2(7),2000个就是2000*1000e^-0.2(7)
请问为什么不能这么算?正确算法是用反导
导数A bacteria population is growing at 1000e^-0.2x bacteria per day.If there are initially 2000 bacteria,then how many bacteria will there be after one week.1个细胞每天增加1000e^-0.2x,一周7天,那1个细胞每天就是1000e^-0.2(7),20
1个细胞每天增加1000e^-0.2x,一周7天,那1个细胞7天就是增加1000e^-0.2(7)才对,可是问的是2000个细胞一周后数量为多少并非问2000个细胞一周后增加的的数目,你可以类比啊,条件给出的相当于速度,实际求位移,你说是不是用反导啊
是曲线还是切线?
满意请采纳。