xIny+2y=2x^3 use implicit differentiation to find y'我算到是y'=6x^2*y-yIny-x/2y但书上答案是y'=6x^2*y-yIny/x+2y我怎麼算也算不到x在分母呢,是书错还是我错...

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xIny+2y=2x^3useimplicitdifferentiationtofindy''我算到是y''=6x^2*y-yIny-x/2y但书上答案是y''=6x^2*y-yIny/x+2y我怎麼算也算

xIny+2y=2x^3 use implicit differentiation to find y'我算到是y'=6x^2*y-yIny-x/2y但书上答案是y'=6x^2*y-yIny/x+2y我怎麼算也算不到x在分母呢,是书错还是我错...
xIny+2y=2x^3 use implicit differentiation to find y'
我算到是y'=6x^2*y-yIny-x/2y
但书上答案是y'=6x^2*y-yIny/x+2y
我怎麼算也算不到x在分母呢,是书错还是我错...

xIny+2y=2x^3 use implicit differentiation to find y'我算到是y'=6x^2*y-yIny-x/2y但书上答案是y'=6x^2*y-yIny/x+2y我怎麼算也算不到x在分母呢,是书错还是我错...
对函数左右求导的话,lny+x*y‘/y+2y'=6x^2,化简合并同类项以后y'=6x^2*y-yIny/x+2y.

xIny+2y=2x^3 use implicit differentiation to find y'我算到是y'=6x^2*y-yIny-x/2y但书上答案是y'=6x^2*y-yIny/x+2y我怎麼算也算不到x在分母呢,是书错还是我错... 存在x,使得sin(x-y)=sinx-xiny,求证明 Z=sin(xy)+xIny分别求对x和y的偏导数 xIny+ye^(xy)=0 求y的导数 求导:Iny=(e^y)sin xIny=(e^y)sin x 求:dy/dx e得y次方然后乘以sin x use elimination to solve each system of equations 例子:X- Y= 1 X + Y= 3 and 3x-y=26 -2x-y= -24 xIny+ye^(xy)=0 求y的导数 利用复合函数求导法求Y的导数 某消费者效用函数为U(x,y)=xIny,消费者的收入为m,xy两商品的价格为Px,Py,求消费者对两商品的需求西经达人.帮个忙. Use logarithmic differentiation to find the derivative of the function. y = (cos 2x)^x求方程导数y = (cos 2x)^x 英语翻译Prove that the curves y=x^3 and y=(x+1)/(x^2 +4) have exactly one point in common,and use differentiation to find the gradient of each curve at this point.题目大意大概是这样:求证弧 y=x^3 和弧 y=(x+1)/(x^2 +4) 恰有一个 1.设集合A={x|-2≤x≤a},B={y|y=2x+3,x∈A},C={y=x2 ,x∈A},若B∪C=B,求a的取值范围2.____you _____in the countryside?Yes.So I ___the life in the countryside?A.Did; use to live; am used toB.Did; use to live;used to calculus,use the method of cylindrical shells to find the volume V generated by rotating the region bounded by the given curves about y-axis,y=2+x-x^2, x + y =2V=( ? ) (x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)= (x+y)(x-y)+(x-y)平方-(x-y)(3x-y) 其中x=-2 y=3分之一 已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y) x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 (x+y)(2x-3y)=? matlab代码错误x=1:0.001:3;>> y=qjf(x);plot(x,y)Error using ^ Inputs must be a scalar and a square matrix.To compute elementwise POWER,use POWER (.^) instead.Error in qjf (line 5)y=(1+( 29/450 - 6^(1/2)/75)*(x-( 6^(1/2)/30 - 1/45))^(-2))^(-1)定