化简i(2i-1)A-2+i B2+i C-2+i D-2-i请说明白

化简i(2i-1)A-2+i B2+i C-2+i D-2-i请说明白 计算(i^2+i)+|i|+(1+i) -I-2I化简 -I-4.2I+I-.2I-(-4.3) fortran程序,subroutine solvereal::i,x,y,mreal::h(i),d(i),a(i),dy(i)h(i)=(1+2*(x-a(i))/(a(i+1)-a(i)))*(((x-a(i+1))/(a(i)-a(i+1)))**2)d(i)=(((x-a(i+1))/(a(i)-a(i+1)))**2)*(x-a(i))m=y(i)*h(i)+dy(i)*d(i)end subroutine solveprogram mainreal::i,sreal::a( 计算:1+i+i^2+i^3+...+i^n (i-2)(1-2i) i*(1-i)^2等于? (1+i)-(2-3i) 复数除法 计算1+i/1-i,1/i,7+i/3+4i （-1+i)(2+i)/-i 复数计算：（1）i+i^2+i^3+.+i^100（2）i^10+i^20+i^30+.+i^80(3)i*i^2*i^3*.*i^100(4)i*i^3*i^5*.*i^99(5)[(1+i)/(1-i)])[(1+i)/(1-i)]^2)[(1+i)/(1-i)]^3.)[(1+i)/(1-i)]^100 Ia+2I+Ia-1I化简 (i=2;i 若i是虚数单位,则复数2i+1+i/i= A.1-i B.1+i C-1+3i.D.1+3i若i是虚数单位,则复数2i+1+i/i=A.1-i B.1+i C-1+3i.D.1+3i 2/1-i-(1+i)²等于?A.1+i B.-1+i C.-1-i D.1-i2/1-i-(1+i)^2等于? i为虚数单位 (-1 2i)*i=?a.2+i.b.2-i.c.-2-i.d.-2+i. 计算1+7i/2-i（其中i是虚数单位）等于 A.1+3i B.-1+3i C.1-3i D.3+i 已知i为虚数单位,则(4+2i)/(1-i)=（ ） A.1+3i B.1-3i C.3-i D.3+i