若Ix+3I+I2-yI+Iz+1I=0,求x-y-z的值.
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若Ix+3I+I2-yI+Iz+1I=0,求x-y-z的值.若Ix+3I+I2-yI+Iz+1I=0,求x-y-z的值.若Ix+3I+I2-yI+Iz+1I=0,求x-y-z的值.x=-3y=2z=-
若Ix+3I+I2-yI+Iz+1I=0,求x-y-z的值.
若Ix+3I+I2-yI+Iz+1I=0,求x-y-z的值.
若Ix+3I+I2-yI+Iz+1I=0,求x-y-z的值.
x=-3 y=2 z=-1 x-y-z=-4
若Ix+3I+I2-yI+Iz+1I=0,求x-y-z的值.
Ix+3I+I2
Ix-5I+Iy+2I+Iz-3I=0 求IxI+IyI+IzI
若Ix+2I+Iy-3I=0,则Ix+yI的值为( ) ,急求答案
IX-1I+IY+ZI+IZ+3I=0,则(x+1)(y+5)(z-1)=?
已知x,y均为整数,且Ix-yI+Ix-3I=1,求x+y的值
不等式I2-xI+Ix+1I
不等式I2-XI+IX+1I
化简Ix+1I+I2-xI
y=Ix+1I+Ix-3I 求值域
IX-3I+IX+5I=?
Ix-5I+Iy+2I+Iz-3I=0 求IxI+IyI+IzI的值这道题怎么做?恳请回答,
若Ix+2I与Iy-3I互为相反数,求Ix+yI的值把方法写出来.
若Ix-1I
求Ix-1I+Ix-2I+Ix-3I+Ix-5I的最小值
Ix+yI+IxI=4 2Ix+yI+3IxI=9 (I I是绝对值) 这个二元一次方程一共有几组解
已知有理数x,y满足Ix-yI+Iy-5I=0,求3x-9y
I I是绝对值的符号IX-1I+IX-2I+IX-3I+。+IX-1997I的最小值!