5a(x-y)^2+10a(y-x)^3
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5a(x-y)^2+10a(y-x)^35a(x-y)^2+10a(y-x)^35a(x-y)^2+10a(y-x)^35a(x-y)^2+10a(y-x)^3=5a(x-y)^2[1+2(y-x)]
5a(x-y)^2+10a(y-x)^3
5a(x-y)^2+10a(y-x)^3
5a(x-y)^2+10a(y-x)^3
5a(x-y)^2+10a(y-x)^3
=5a(x-y)^2[1+2(y-x)]
=5a(x-y)^2(2y-2x+1)
5a(x-y)²+10a(y-x)³
=5a(y-x)²+10a(y-x)³
=5a(y-x)²(1+2y-2x)
5a(x-y)^2+10a(y-x)^3
10a(x-y)^2+5a(x-y)
(1)x(x+10)-2(3x-2) 分解因式y(2y+1)-y(y-1)+1 2x(2x-y)+y(y-2x) 2y(y-2)-y(y-4)-1 x(x+8)-8(x+2) (a+2)(a-2)-5 (x-3)(a-2)-5 (x+3)(x+4)+4分之1
因式分解:10a(x-y)^2-5b(y-x)
因式分解2m(x-3)+(x-3) 5(x-y)^3+10(y-x)^2 -ab(x-y)^3+a(y-x)^3-ac(x-y)^3 帮我哦2m(x-3)+(x-3)5(x-y)^3+10(y-x)^2-ab(x-y)^3+a(y-x)^3-ac(x-y)^3 这是3题哦
(1)2(a^2-ab)-2a^2+3ab (2)5(2x-7y)-3(4x-10y) (3)(x+y)-[3x+(-x+y)]
(2x+y)(2x-3y)+x(2y+y) 2a(x-y)-4b(x-y)
分解因式10a^2(x+y)^2-5a(x+y)^3
(1)(x+y)^2-(x+y)^3(2)(x-y)-(x-y)^3(3)(x-y)^2-(y-x)^3(4)2(x-y)-3(y-x)^2(5)4ab(a=b)^2-6a^2b(a+b)(6)(x+y)^2(x-y)+(x+y)(x-y)^2(7)2a(a-3)^2-6a^2(3-a)+8a(a-3)(8)24xy^2z^2(x+y-z)-32xyz(z-x-y)^2+8xy(z-x-y)(9)(a-b)(b-a)^n(b-a)^2n-1 [两解)(10)2^2=3,2^b
分解因式:10a(x-y)^2-5a(y-x)^3
10a(x-y)²-5a(y-x) 因式分解
36a^3(x-y)^2/27a(y-x)
(3a^3/X+Y)^3*(X^2-Y^2)除以(Y-X/Y+X)^2
(1)x^2*x^8+x^13/x^3 (2)a^19/a^12/a^3 (3) (x-2y)^5/(2y-x)^3 (4)(x-y)^5/(x-y) (5)(x-y)^6/(y-x)^4
A=((x,y)/2x+y=10),B=((x,y)/3x-y=5),求A交B,并且说明他的意义
如果方程组x-y=a-3,2x+y=5的解x、y满足x>0,y
因式分解:3a(x-y)-(x-y)
3a(x-y)-(y-x) 因式分解