sin(X-π/3)-cos(x+π/6)+√3cosx
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sin(X-π/3)-cos(x+π/6)+√3cosxsin(X-π/3)-cos(x+π/6)+√3cosxsin(X-π/3)-cos(x+π/6)+√3cosxsin(x-π/3))-cos(
sin(X-π/3)-cos(x+π/6)+√3cosx
sin(X-π/3)-cos(x+π/6)+√3cosx
sin(X-π/3)-cos(x+π/6)+√3cosx
sin(x-π/3))-cos(x+π/6)+√3cosx
=sinxcosπ/3-cosxsinπ/3-cosxcosπ/6+sinxsinπ/6+√3cosx
=1/2*sinx-√3/2*cosx-√3/2*cosx+1/2*sinx+√3cosx
=sinx
cos(x+π/3)是不是等于sin(x-π/6)
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