f(x)=2sin(2x-∏/6)+1如何由y=2sin2x得到

设f=[sin(2/x)]=1+cosx,求f(x),f[cos(2/x)].如题! f(x)=x^5-2(x^3)+3/x,f'(-1)=A -11 B -2 C 2 D 6 E 11如果f(x)=cos(lnx) x>0,那么f'(x)=A -sin(lnx) B sin(lnx) C -sin(lnx)/x D sin(lnx)/x E sin(lnx/x)f(x)=x*(2^x),f'(x)=A 2^x(x+ln2) B 2^x(1+ln2) C x*2^x*ln2 D 2^x(1+x*ln2) E x*2*(1+ln2)f(x)=x^3-x+2 如 若f(x)=sin πx/6,则f(1)+f(2)+...+f(102)=? f(sin 2/x )=1+cosx 求f(x) 证明f(x)=sin^2x/1-sinx的奇偶性如题... 傅里叶级数作图f（x）=2sin[x] - sin[2x] + 2/3sin[3x] - 1/2sin[4x]我用mathematica输入程序Plot[{2sin[x],-2sin[x],2sin[x] - sin[2x],-2sin[x] + sin[2x],2sin[x] - sin[2x] + 2/3sin[3x],-2sin[x] + sin[2x] - 2/3sin[3x],2sin[x] - sin[2x] + 2/3si f(x)=(6sin^4x-7sin^2x+2)/(sin^2x-cos^2x) f(sin^2x)=x/sinx 求f(x) 若f(x)=sin(∏x/3),则f(1)+f(2)+f(3)+...+f(2003)= f(x)={(1-e^x)/sin(x/2) ,x>0 ;ae^2x,x 设函数f(x)=sinπ/6（x),则f(1)+f(2)+f(3)+…f(2008)=? 设函数f(x)=sinπ/6（x),则f(1)+f(2)+f(3)+…f(2008)=? f(x)=（1+cotx)sin^2x-2sin(x+π/4)sin(x-π/4)还有一题, 已知函数f(x)=(1+1 anx)sin^2x+m sin(x+π/4)sin(x-π/4) f(x)=sin(2x+π/6)怎么求导 f(x)=sin^2x+sinxcosx-1/2,化简 f(x)=(1+1/tanx)sin(x)^2化简 化简f(x)=(1+cos2x)sin^2x