化简f(x)=(1+cos2x)sin^2x
来源：学生作业帮助网 编辑：六六作业网 时间：2024/11/28 03:13:17
化简f(x)=(1+cos2x)sin^2x化简f(x)=(1+cos2x)sin^2x化简f(x)=(1+cos2x)sin^2xf(x)=(1+cos2x)sin^2x=(1+cos2x)(1-c
化简f(x)=(1+cos2x)sin^2x
化简f(x)=(1+cos2x)sin^2x
化简f(x)=(1+cos2x)sin^2x
f(x)=(1+cos2x)sin^2x
=(1+cos2x)(1-cos2x)/2
=(1-cos^22x)/2
=sin^22x/2
=[(1-cos4x)/2]/2
=1/4-1/4*cos4x
f(x)=(1+2cos2x)(1-cos2x)/2=[1-(cos2x)^2]/2=[1-(1+cos4x)/2]/2=1/4-cos4x/4
f(x)=(1+cos2x)sin^2x
=(1+2cos²x-1)sin²x
=2cos²xsin²x
=1/2×4cos²xsin²x
=1/2×（2cosxsinx）²
=（sin²2x）/2
化简f(x)=(1+cos2x)sin^2x
已知f(sin-1)=cos2x+2,求f(x)
已知函数f(x)=1+cos2x－2sin^2(x-30°).化简
f(sin x)=cos2X 那么f(cos x)=
f(x)=1+sin(2x)-根号3 cos2x,|f(x)-m|
f(x)=1+sin(2x)-根号3 cos2x |f(x)-m|
化简f(x)=cos2x+sinxcosx+1
f(x)=(cos2x-1)*cosxcosx 化简
设f(sin x)=cos2x+1,求f(cos x).
求一道高数里的函数题f(sin x)=cos2x+1,求f(cos x).
化简f (x)=2cos2x+sin2x-4cox要有过程……2cos2x+sin^2x-4cos
已知函数f(x)=cos2x/[sin(π/4-x)]
化简函数f(x)=cos2x/sin(45'-x)
设函数f(cos2x)=2sin∧2x,则f(1/2)=
f（x）=4sin^2（π/4+x）-2根号3cos2x-1化简!
已知函数f(x)=（4cos^4x-2cos2x-1）/[sin(π/4+x)·sin^2(π/4-x)]化简
已知函数f(x)=（4cos^4x-2cos2x-1）/[sin(π/4+x)·sin(π/4-x)]化简
f(sinx)=2sin²x-cos2x