线性代数的问题,应该不难,For which values of "a" will be the following system have no solutions?Exactly one solution?Infinitely many solutions?x + 2y - 3z =43 x - y + 5z =24 x + y + (a^2-14)z =a+4上面是a+2不是a+4

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线性代数的问题,应该不难,Forwhichvaluesof"a"willbethefollowingsystemhavenosolutions?Exactlyonesolution?Infinitel

线性代数的问题,应该不难,For which values of "a" will be the following system have no solutions?Exactly one solution?Infinitely many solutions?x + 2y - 3z =43 x - y + 5z =24 x + y + (a^2-14)z =a+4上面是a+2不是a+4
线性代数的问题,应该不难,
For which values of "a" will be the following system have no solutions?Exactly one solution?Infinitely many solutions?
x + 2y - 3z =4
3 x - y + 5z =2
4 x + y + (a^2-14)z =a+4
上面是a+2不是a+4

线性代数的问题,应该不难,For which values of "a" will be the following system have no solutions?Exactly one solution?Infinitely many solutions?x + 2y - 3z =43 x - y + 5z =24 x + y + (a^2-14)z =a+4上面是a+2不是a+4
将方程组的增广矩阵作初等行变换,分为梯矩阵:
1 2 -3 4
0 -7 14 -10
0 0 a^2-16 a-2
可知:当a=4 或 -4 时,方程组无解.
当a!=4 且 a!= -4 时,方程组有唯一解.

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