已知M={(x,y)|y=-x^2+mx-1},N={(x,y)|y=-x+3,0

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已知M={(x,y)|y=-x^2+mx-1},N={(x,y)|y=-x+3,0已知M={(x,y)|y=-x^2+mx-1},N={(x,y)|y=-x+3,0已知M={(x,y)|y=-x^2+

已知M={(x,y)|y=-x^2+mx-1},N={(x,y)|y=-x+3,0
已知M={(x,y)|y=-x^2+mx-1},N={(x,y)|y=-x+3,0

已知M={(x,y)|y=-x^2+mx-1},N={(x,y)|y=-x+3,0
由已知:是两个函数图象有公共点,
再转化成方程-x^2+mx-1=-x+3在0