2{(根号a-1)+根号(b+2)+根号c+1)]=a+b+c+5,求a+b+c,

2{(根号a-1)+根号(b+2)+根号c+1)]=a+b+c+5,求a+b+c,
2{(根号a-1)+根号(b+2)+根号c+1)]=a+b+c+5,求a+b+c,

2{(根号a-1)+根号(b+2)+根号c+1)]=a+b+c+5,求a+b+c,
a+b+c+5-2[根号(a-1)+根号(b+2)+根号(c+1)] = [a-1 -2根号(a-1) +1] + [b+2 -2根号(b+2) +1] + [c+1 -2根号(c+1) +1] = [根号(a-1) -1]^2 + [根号(b+2) -1]^2 + [根号(c+1) +1]^2 = 0
a=1
b=-2
c=-1
a+b+c=-2

a=1
b=-2
c=-1
a+b+c=-2 x