1/6+1/24+1/60+1/120+----+1/117600
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1/6+1/24+1/60+1/120+----+1/1176001/6+1/24+1/60+1/120+----+1/1176001/6+1/24+1/60+1/120+----+1/117600我
1/6+1/24+1/60+1/120+----+1/117600
1/6+1/24+1/60+1/120+----+1/117600
1/6+1/24+1/60+1/120+----+1/117600
我们看分子先
6=1*2*3
24=2*3*4
60=3*4*5
120=4)5)6
.
117600=48*49*50
分母是连续三个自然数相乘,而且每一项的开始一个自然数都加1
分母就是=n(n+1)(n+2)
1/1*2*3+1/2*3*4+1/3*4*5+.+1/n(n+1)(n+2)+.
sn=1/2*[1/1*2-1/2*3+1/2*3-1/3*4+1/3*4-1/4*5+.+1/n(n+1)-1/(n+1)(n+2)]
=1/2*[1/2-1/(n+1)(n+2)]
=1/4-1/2(n+1)(n+2)
原式到了第48项的加和,将48带入n,得到
原式=306/1225
1
1/6+1/24+1/60+1/120+----+1/117600
1/6+1/24+1/60+1/120+1/210+1/336=?
1/6+1/24+1/60+1/120+1/210的简便计算
1/6+1/24+1/60+1/120+1/210的简便计算
336/1+6/1+24/1+60/1+120/1+210/1336/1+6/1+24/1+60/1+120/1+210/1/是除没的错比如60/1=60分之1
1/6+1/24+1/60+1/120=?能简便吗?
1/6,1/24,1/60,1/120,------,求通项,并求出前n项和
1/6、1/24、1/60、1/120,第20个分数是?
x+1/6+1/24+1/60+1/120+1/336=1/4,则x是多少,
x+1/6+1/24+1/60+1/120+1/336=1/4,则x是多少
1/2-1/6-24/1-1/120
简便运算:1/6+1/24+1/60+1/40
计算:6/1+24/1+40/1+60/1
计算题:1/6+1/24+1/60+1/40
观察下面分数串:1/6,1/24,1/60,1/120,写出它的第20个分数
1,2,6,24,120,( )
1 2 6 24 120 720 ()
1 2 6 24 120 720 )