求证 (sin2α-cos2α)^2=1-sin4x

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求证(sin2α-cos2α)^2=1-sin4x求证(sin2α-cos2α)^2=1-sin4x求证(sin2α-cos2α)^2=1-sin4x(sin2α-cos2α)^2=(sin2α)^2

求证 (sin2α-cos2α)^2=1-sin4x
求证 (sin2α-cos2α)^2=1-sin4x

求证 (sin2α-cos2α)^2=1-sin4x
(sin2α-cos2α)^2=(sin2α)^2+(cos2α)^2-2sin2αcos2α
=1-2sin2αcos2α
=1-sin4α