x2y2+xy-x2-y2＋x＋y＋2分解因式,
来源：学生作业帮助网 编辑：六六作业网 时间：2024/11/24 17:50:37
x2y2+xy-x2-y2＋x＋y＋2分解因式,x2y2+xy-x2-y2＋x＋y＋2分解因式,x2y2+xy-x2-y2＋x＋y＋2分解因式,原式=(x²y²-x²-y
x2y2+xy-x2-y2＋x＋y＋2分解因式,
x2y2+xy-x2-y2＋x＋y＋2分解因式,
x2y2+xy-x2-y2＋x＋y＋2分解因式,
原式=(x²y²-x²-y²+1)+(xy+x+y+1)
=[x²(y²-1)-(y²-1)]+[x(y+1)+(y+1)]
=(x²-1)(y²-1)+(x+1)(y+1)
=(x+1)(x-1)(y+1)(y-1)+(x+1)(y+1)
=(x+1)(y+1)[(x-1)(y-1)+1]
=(x+1)(y+1)(xy-x-y+2)
（X²Y²-X²-Y²+1）+（XY+X+Y+1）=（X²Y²-X²-Y²+1）+（X+1）（Y+1）=X²（Y²-1）-（Y²-1）+（X+1）（Y+1）=（Y²-1）（X²-1）+（X+1）（Y+1）=(x+1)(x-1)(y+1)(y-1)+(x+1)(y+1)=(x+1)(y+1)[(x-1)(y-1)+1]
x2y2+xy-x2-y2＋x＋y＋2分解因式,
已知x2+4y2+x2y2+1=6xy,则(x4-y4)/(2x2+xy-y2)*(2x-y)/(xy-y2)/(x2+y2/y)2=
已知:x-y= -2 求(x2+y2)2-4xy(x2+y2)+4x2y2的值
(x2+y2)(x2-xy+y2)-2x2y2因式分解
若实数x,y满足x2+y2+x2y2-4xy+1=0,则(x+y)2的值为
因式分解x2＋y2－x2y2－4xy－1；
已知x2+4y2+x2y2-6xy+1=0,求 x4-y4/2x-y 乘 2xy-y2/xy-y2 除以（x2+y2/xy）2乘1/x+y的值
先化简,后求值,其中 x-y=1,xy=2,(1)x3y-2x2y2+xy3 (2)x2+y2
设x2y2-20xy+x2+y2+81=0,求x+y的值
已知xy/x+y=1/3,x2y2/x2+y2=1/5,求xy的值.
已知：x-y+1=0,xy-2x-2y-7=0,求x2+y2以及4x2y2-x4-y4.
x2+y2-x2y2-4xy-1
x4－2x2y2－3x2＋6y2因式分解
化简求值（2X2-2y2）-3（X2y2+X2）+3（X2y2+y2）,其中X=-1,y=2
（2x2-2y2）-3（x2y2+x2）+3x2y2+y2.提示：x=-1,y=2 化简求值
已知实数x,y满足x2+y2=2x,求x2y2的范围
a3x3 + x3 - a3y3 -y3 x4- 4x3+ 4x2 - 9 (x+y)2 - 4(x+y) +4 (2+ y2 )(x2- xy+ y2) -2x2y2 几次方不会打.....就这样打了一下...
因式分解 x2＋4xy＋4y2－2x－4y－35