quickly!已知a

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quickly!已知aquickly!已知aquickly!已知aa0,a-1由a0，即点P在第2象限，关于原点对称的A点则在第4象限，坐标为（a*a+1，a-3）4向限a^2>0-a^2-1-a>0

quickly!已知a
quickly!
已知a

quickly!已知a
a0,a-1

由a<0可得-a*a-1<0，-a+3>0，即点P在第2象限，关于原点对称的A点则在第4象限，坐标为（a*a+1，a-3）

4向限

a^2>0
-a^2-1<-1
-a>0
-a+3>3
A(1+a^2,a-3)
确定点A在第4象限

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