关于x的方程根号(2x-4)-根号(x+k)=1有一个增根为4,求k

关于x的方程根号(2x-4)-根号(x+k)=1有一个增根为4,求k
关于x的方程根号(2x-4)-根号(x+k)=1有一个增根为4,求k

关于x的方程根号(2x-4)-根号(x+k)=1有一个增根为4,求k
两边平方得到2x-4+x+k-2√(2x-4)*(x+k)=1.移向后两侧在平方得到（3x+k-5）^2=4(2x-4)*(x+k).将x=4带入并整理得到k^2-2k-15=o,k1=5,k2=-3.将x和k的值带入原方程,k=5,x=4时方成不成立,k=-3.x=4时,方程成立.x=4为方程曾根,所以k的值应该为5.

将4代入即可 4-根号(4+k)=1
移项 两边平方 9=4+k
k=5

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soldiers の
ai
Ni
★
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I swear

soldiers の
ai
Ni
★
☆
★
☆
really
arrived






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增根是3，即X=3 代入原式： （8-4）-根号（4+K）=1
根号（4+K）=3
4+K=9
K=5