has( )cuily hair A;a lou B;many C;a D;\
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has()cuilyhairA;alouB;manyC;aD;\has()cuilyhairA;alouB;manyC;aD;\has()cuilyhairA;alouB;manyC;aD;\Dhas
has( )cuily hair A;a lou B;many C;a D;\
has( )cuily hair A;a lou B;many C;a D;\
has( )cuily hair A;a lou B;many C;a D;\
D
has curly hair
头发不可数
D;\ hair不可数
D
curly hair不可数