x3-5x2+5x-4x5+1/4x9a4+11a2b2+4b4(a2-5b2)2+(4ab)2a2-2a+4b-4b2

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x3-5x2+5x-4x5+1/4x9a4+11a2b2+4b4(a2-5b2)2+(4ab)2a2-2a+4b-4b2x3-5x2+5x-4x5+1/4x9a4+11a2b2+4b4(a2-5b2)

x3-5x2+5x-4x5+1/4x9a4+11a2b2+4b4(a2-5b2)2+(4ab)2a2-2a+4b-4b2
x3-5x2+5x-4
x5+1/4x
9a4+11a2b2+4b4
(a2-5b2)2+(4ab)2
a2-2a+4b-4b2

x3-5x2+5x-4x5+1/4x9a4+11a2b2+4b4(a2-5b2)2+(4ab)2a2-2a+4b-4b2
x3-5x2+5x-4
=(x³-4x²)-x²+5x-4
=x²(x-4)-(x-4)(x-1)
=(x-4)(x²-x+1)
x5+1/4x
=1/4x(4x4+1)
=1/4x(4x4+4x²+1-4x²)
=1/4x[(2x²+1)²-4x²]
=1/4x(2x²+2x+1)(2x²-2x+1)
9a4+11a2b2+4b4
=(9a4+12a2b2+4b4)-a²b²
=(3a²+2b²)-a²b²
=(3a²+ab+2b²)(3a²-ab+2b²)
(a2-5b2)2+(4ab)2
=a4-10a²b²+25b4+16a²b²
=a4+6a²b²+25b4
=a4+10a²b²+25b4-4a²b²
=(a²+5b²)²-4a²b²
=(a²+2ab+5b²)(a²-2ab+5b²)
a2-2a+4b-4b2
=(a+2b)(a-2b)-2(a-2b)
=(a-2b)(a+2b-2)

分解因式:-27x3+8 ,(x2-5x+2)(x2-5x+4)-24 ,x5+x4+x3+x2+x1+1 x1-x2+x3=1x2-x3+x4=21若x1,x2,x3,x4,x5满足方程组 x3-x4+x5=3x4-x5+x1=4x5-x1+x2=5求x2 x3 x4的值2已知 x1+x4+x6+x7=39 x2+x4+x5+x7=49 x3+x5+x6+x7=41 x4+x7=13 x5+x7=14 x6+x7=9 x1+x2+x3+x4+x5+x6+x7=9求x7的值若x1,x2,x3,x4,x5满足方程组 x1-x x1-x2+x3=1 x2-x3+x4=2 x3-x4+x5=3 x4-x5+x1=4 x5-x1+x2=5 求x1,x2,x3,x4,x5 求非齐次线性方程组的通解x1+3x2+5x3-4x4=1x1+3x2+2x3-2x4+x5=-1x1-2x2+x3-x4-x5=3x1+2x2+x3-x4-x5=3 求齐次线性方程组x1+2x2+x3+x4+x5=1 2x1+4x2+3x3+x4+x5=2 -x1-2x2+x3+3x4-3x5=5 2x3+4x-2x5=6的一般解 若x1,x2,x3,x4,x5满足方程组:x1-x2+x3=1 x2-x3+x4=2 x3-x4+x5=3 x4-x5+x1=4 x5-x1+x2=5 求x2,x3,x4的少打了个字,是求x2,x3,x4的值 解方程组:x1+x2+x3+x4+x5=7 3x1+2x2+x3+x4-3x5=-2 x2+2x3+2x4+6x5=23 5x1+4x2-3x3+3x4-x5=10 求非其次线性方程组 {x1+2x2+x3+x4+x5=1x1+2x2+x3+x4+x5=12x1+4x2+3x3+x4+x5=2-x1-2x2+x3+3x4-x5=5 2x3+4x4-2x5=6 的一般解 求线性方程组的全部解,并用对应导出组的基础解系表示X1+3X2+5X3-4X4=1 X1+3X2+2X3-2X4+X5=-1 X1-2X2+X3-X4-X5=3 X1-4X2+X3+X4-X5=3 X1+2X2+X3-X4+X5=-1 关于非齐次线性方程组的,大X1+X2+X3+X4+X5=73X1+2X2+X3+X4-3X5=-2括X2+2X3+2X4-3X5=23号5X1+4X2-3X3+3X4-X5=12X是x不是乘号哦 已知数据X1,X2,X3,X4,X5的平均数是X拔,则一组新数据X1+1,X2+2,X3+3,X4+4,X5+5的平均数是? 如果一组数据x1,x2,x3,x4,x5的平均数是x拔,则另一组数据x1+1,x2+2,x3+3,x4+4,x5+5的平均数是多少 求下列非齐次线性方程组的通解(1){x1+x2+x3+x4+x5=2;x1+2x2-4x5=-2;x1+2x3+2x4+6x5=6;4x1+5x2+3x3+3x4-x5=4}(2){x1-x2+5x3-x4=1;x1+x2-2x3+3x4=1;2x1+3x3+2x4=2;2x1+4x2-11x3+10x4=2}(3){x1+x2+x3+x4+x5=1;3x1+2x2+x3+x4-3x5=0 设总体X~N(12,4),有n=5的样本X1,X2,X3,X4,X5,求P{min(X1,X2…,X5) 因式分解X5-X4+2X3-2X2+2X-4 x5-x4+x3-x2+x-1因式分解 X5-X4+X3+X2+X+1因式分解 求解一个方程急 X(1次方)+X2+X3=5 X2+X3+X4=1 X3+X4+X5=-5 X4+X5+X1=-3 X5+X1+X2=2 求X的值,