x5-x4+x3-x2+x-1因式分解

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x5-x4+x3-x2+x-1因式分解x5-x4+x3-x2+x-1因式分解x5-x4+x3-x2+x-1因式分解x5-x4+x3-x2+x-1=x4(x-1)+x2(x-1)+(x-1)=(x-1)

x5-x4+x3-x2+x-1因式分解
x5-x4+x3-x2+x-1因式分解

x5-x4+x3-x2+x-1因式分解
x5-x4+x3-x2+x-1
=x4(x-1)+x2(x-1)+(x-1)
=(x-1)(x4+x2+1)
=(x-1)(x4+2x2+1-x2)
=(x-1)[(x2+1)2-x2]
=(x-1)(x2+x-1)(x2-x+1)

原式=x4(x-1)+x²(x-1)+(x-1)
=(x-1)(x4+x²+1)
=(x-1)[(x4+2x²+1)-x²]
=(x-1)[(x²+1)²-x²]
=(x-1)(x²+x+1)(x²-x+1)

您好！
x^5-x^4+x^3-x^2+x-1
=x^4(x-1)+x^2(x-1)+x-1
=(x^4+x^2+1)(x-1)
=(x^4+2x^2+1-x^2)(x-1)
=[(x^2+1)^2-x^2](x-1)
=(x^2+1+x)(x^2+1-x)(x-1)
=(x^2+x+1)(x^2-x+1)(x-1)
希望我的答案能够帮到你~
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