(x-2)(x+3)+(2-x)∧2-(x-2)(2x-3)=20
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(x-2)(x+3)+(2-x)∧2-(x-2)(2x-3)=20(x-2)(x+3)+(2-x)∧2-(x-2)(2x-3)=20(x-2)(x+3)+(2-x)∧2-(x-2)(2x-3)=207
(x-2)(x+3)+(2-x)∧2-(x-2)(2x-3)=20
(x-2)(x+3)+(2-x)∧2-(x-2)(2x-3)=20
(x-2)(x+3)+(2-x)∧2-(x-2)(2x-3)=20
7
因为(2-x)^2=(x-2)^2
原试可化为=（x-2)(x+3+x-2-2x+3)=20
=4(x-2)=20
所以x=7
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