数学x–y+3z=28 x:y:z=1:2:5
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数学x–y+3z=28x:y:z=1:2:5数学x–y+3z=28x:y:z=1:2:5数学x–y+3z=28x:y:z=1:2:5设x=t,y=2t,z=5t则t-2t+15t=28t=2所以:x=
数学x–y+3z=28 x:y:z=1:2:5
数学x–y+3z=28 x:y:z=1:2:5
数学x–y+3z=28 x:y:z=1:2:5
设x=t,y=2t,z=5t
则t-2t+15t=28
t=2
所以:
x=2,y=4,z=10
设k,变成x=k,y=2k,z=5k
那么原式就变成k-2k+15k=28
求出k,x,y,z求出
X y z 依次是2 4 10
2-4-10
数学x–y+3z=28 x:y:z=1:2:5
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