8x+3y=110008x*8%+3y*12%=10008x+3y=11000 8x*8%+3y*12%=1000二元一次方程解
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/23 22:22:16
8x+3y=110008x*8%+3y*12%=10008x+3y=110008x*8%+3y*12%=1000二元一次方程解8x+3y=110008x*8%+3y*12%=10008x+3y=110
8x+3y=110008x*8%+3y*12%=10008x+3y=11000 8x*8%+3y*12%=1000二元一次方程解
8x+3y=110008x*8%+3y*12%=1000
8x+3y=11000 8x*8%+3y*12%=1000二元一次方程解
8x+3y=110008x*8%+3y*12%=10008x+3y=11000 8x*8%+3y*12%=1000二元一次方程解
由2 0.64x+0.36y=1000
8x+4.5y=12500 3
3-1 0.5y=1500
y=3000
x=250
方程化为8x+3y=11000
16x+9y=25000
再化
16x+6y=22000
16x+9y=25000
x=1000,y=1000
【2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2】/2(x-y)^2=
(x+y)/y=8/3则x/y=__ y/x-y=___
(x+y)/y=8/3则x/y=__ y/x-y=___
12y(x-y)^2-8(x-y)^3=?
已知x,y为正整数,并且x*y+x+y=71,x*x*y+x*y*y=880,求3*x*x+8*x*y+3*y*y的值
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
(2x+y)²+(x+3y)(x-3y)-x(5x+8y)因式分解
[2(x-y)^5-8(x-y)^2(x+y)+6y(x-y)^2]÷2(x-y)^2[2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2]÷2(x-y)^2
9y=3x-(x-1),4(x+y)-(2x+4)=8y
3x-2y=9 x-3y=2 x+y=5 x+2y=3 y=x 2x+y=8
x+y=1 5x-2y=8 3x-y=7 2x-y=3x表示y和用y表示x
已知实数x.y满足根号(x+y-8)+根号(8-x-y)=根号(3x-y-4)+根号(x-2y+7),求x,y
已知x.x+y.y-6x-8y+25=0,求3x.x+5y的值
若x-y不等于0,2x-3y=0,则分式(10x-11y)/(x-y)的值是()?(10x-11y)/(x-y) =[(8x-8y)+(2x-3y)]/(x-y) =8为什么8X-8Y=8?(10x-11y)/(x-y)=[(8x-8y)+(2x-3y)]/(x-y)=8+(2x-3y)]/(x-y)=8+0=8
{x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0
18(x+y)^8(x-y)^7÷[3(x+y)^3(x-y)^3]^2
(x-y)^3·(y-x)^4 / [(x-y)^8/(y-x)^3]
(3x-4y)(5x-4y)-(7x-8y)(6y-5x)