cos(π/2+a)=1/3 则cos(π+2a)=

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cos(π/2+a)=1/3则cos(π+2a)=cos(π/2+a)=1/3则cos(π+2a)=cos(π/2+a)=1/3则cos(π+2a)=cos(π+2a)=cos[2(π/2+a)]=2

cos(π/2+a)=1/3 则cos(π+2a)=
cos(π/2+a)=1/3 则cos(π+2a)=

cos(π/2+a)=1/3 则cos(π+2a)=
cos(π+2a)
=cos[2(π/2+a)]
=2cos(π/2+a)²-1
=2×(1/3)²-1
=2/9-1
=-7/9