x^2-ax-a-1
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x^2-ax-a-1x^2-ax-a-1x^2-ax-a-1x^2-ax-a-1=(x²-1)-(ax+a)=(x+1)(x-1)-a(x+1)=(x+1)(x-1-a)=[x-(a+1)]
x^2-ax-a-1
x^2-ax-a-1
x^2-ax-a-1
x^2-ax-a-1
=(x²-1)-(ax+a)
=(x+1)(x-1)-a(x+1)
=(x+1)(x-1-a)
=[x-(a+1) ](x+1)
即x^2-ax-a-1
x^2-ax-a-1
因式分解:x^3-ax^2-2ax+a^2-1
把a+ax+ax^2+x^2-1因式分解
若A={x|ax^2-ax+1
关于x的不等式ax^2+ax+a-1
x^3+ax^2+ax+a-1因式分解谢谢了
若集合A={x丨ax^2-ax+1
ax^2-a^2x-x+a怎样因式分解为(x-a)(ax-1),
关于x不等式ax^2+ax+a
2a(x+1)^2-2ax
ax^2-(a+1)x+1
ax^2-(a-1)x+1
ax^2-(a-1)x+1
解不等式ax^2-x+1-a
x²-2ax+a²-1
(a+1)/x+2ax+4
x^2-ax+1-4a
求该函数(x^2 - x - 1/a)e^ax (a>导数e^ax * (ax+2)(x-1)