当m∈{m|m＞1}时,m+1/(m-1)的最小值要如何求?

当m∈{m|m＞1}时,m+1/(m-1)的最小值要如何求? 当m= 时,2m(3m-5)+3m(1-2m)=14 当m=1/2时,求15m²-9-{-4m²+[5m-8m²-(2m²-m)+9m²]-3m} 已知m＞4,化简|m-4|+|7-2m|+|m×m-2m+1|-|m×m-2m-3| (M/1):(M/0. (((m>=1) & (m m*m-5m-1=0则2m*m-5m+1/m*m 已知m*m+m-1=0,求m*m*m+2m*m-2005 设m>1,当[(m-1)!+1]/m时,m必为质数的证明 当m+1/m=3时,m^2+1/m^2的值为 当m+1/m等于3时,m平方+1/m平方的值为 当m=1时,-2m^2-【-4m^2+(-m^2)】的值为 当|m|=-m时,化简|m-1|-|m-2|所得结果? 如果M>O,那么当M为多少时,M+1/M有最小值 当m>6时,化简|m-1|-|5-m|+|m-6| 1 当m 当1≤m x-m＞3-2m 当x＞1时 m取何值