已知|x+y-1/2|+(2y+6z+5)²+(3z+x+1)²=0,则2x-y+z=
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已知|x+y-1/2|+(2y+6z+5)²+(3z+x+1)²=0,则2x-y+z=已知|x+y-1/2|+(2y+6z+5)²+(3z+x+1)²=0,则2
已知|x+y-1/2|+(2y+6z+5)²+(3z+x+1)²=0,则2x-y+z=
已知|x+y-1/2|+(2y+6z+5)²+(3z+x+1)²=0,则2x-y+z=
已知|x+y-1/2|+(2y+6z+5)²+(3z+x+1)²=0,则2x-y+z=
绝对值和平方都大于等于0,相加等于0
则只能都等于0
所以x+y-1/2=0
2y+6z+5=0
3z+x+1=0
解方程组,求出x,y,z
然后代入算一下就行
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已知|x+y-1/2|+(2y+6z+5)²+(3z+x+1)²=0,则2x-y+z=