数列{An}满足A1=1,An+1=\/An+An+1/4(n(-N),求该数列通项公式请问这种问题该从何处着手?

数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an 已知数列{an}满足a1=1 an+1=an/(3an+1) 则球an 数列{an}满足a1=1 an+1=2n+1an/an+2n 已知数列{an}满足an+1=an+n,a1等于1,则an=? 数列｛an｝满足a1=1,且an=an-1+3n-2,求an 数列an满足a1=2,an+1=4an+9,则an=? 已知数列{an}满足an+1=2an+3.5^n,a1=6.求an 数列an满足a1=2,an+1=an²求an 数列an满足a1=2,an+1=an²求an 数列[An]满足An+1-An+3=0,且A1=-5.求An. 已知数列{an}中满足(An+1-An)(An+1+An)=16,且a1=1,an 已知数列an满足 a1=1/2,an+1=3an/an+3求证1/an为等差数列已知数列an满足 a1=1/2,an+1=3an/an+3求证1/an为等差数列 数列an满足a1=1/2,a1+a2+a3……an=n^2an,则an 已知数列{an}满足a1=1/2,an+1=3an+1,求数列{an}通项公式 数列an满足a1=1/2 an+1=an/(2an+3) 猜想数列通项公式 已知数列{An}满足A1=1,An+1=2An+2^n.求证数列An/2是等差数列 急!.数列{an}满足a1=2,an+1=-1/an+1,则a2010=? 已知数列{an}满足a(n+1)=an+n,a1=1,则an=