求f(x,y)=4(x-y)-x^2-y^2的极值
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求f(x,y)=4(x-y)-x^2-y^2的极值求f(x,y)=4(x-y)-x^2-y^2的极值求f(x,y)=4(x-y)-x^2-y^2的极值f(x,y)=4(x-y)-x^2-y^2=-(x
求f(x,y)=4(x-y)-x^2-y^2的极值
求f(x,y)=4(x-y)-x^2-y^2的极值
求f(x,y)=4(x-y)-x^2-y^2的极值
f(x,y)=4(x-y)-x^2-y^2=-(x-2)²-(y+2)²+8
因为(x-2)²≥0,(y-2)²≥0
所以f(x,y)=4(x-y)-x^2-y^2=-(x-2)²-(y+2)²+8≤8
所以f(x,y)=4(x-y)-x^2-y^2存在最大值8,且此时x=2,y=-2
y当参数 求x偏导 4-2x=0 x=2
x当参数 求y偏导 -4-2y=0 y=-2(原理我也不懂)
fmax=8
或者全都配方 f(x、y)=-(x-2)2-(y+2)2+8
自然x=2 y=-2 有最大值 无最小值
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