求满足2X^3-3X^2+(2-Y)X+Y-7=0的正整数X,Y的值
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求满足2X^3-3X^2+(2-Y)X+Y-7=0的正整数X,Y的值求满足2X^3-3X^2+(2-Y)X+Y-7=0的正整数X,Y的值求满足2X^3-3X^2+(2-Y)X+Y-7=0的正整数X,Y
求满足2X^3-3X^2+(2-Y)X+Y-7=0的正整数X,Y的值
求满足2X^3-3X^2+(2-Y)X+Y-7=0的正整数X,Y的值
求满足2X^3-3X^2+(2-Y)X+Y-7=0的正整数X,Y的值
化简得2x^3-3x^2+2x-7=(x-1)y
所以 y = 2x^2-x+1-6/(x-1)
所以6/(x-1)为整数
所以x可以取得的值为2,3,4,7
代入可以得对应的y
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