sin(A+B)除sin(A-B)=p除q,则tanA除tanB=加油加油

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sin(A+B)除sin(A-B)=p除q,则tanA除tanB=加油加油sin(A+B)除sin(A-B)=p除q,则tanA除tanB=加油加油sin(A+B)除sin(A-B)=p除q,则tan

sin(A+B)除sin(A-B)=p除q,则tanA除tanB=加油加油
sin(A+B)除sin(A-B)=p除q,则tanA除tanB=
加油加油

sin(A+B)除sin(A-B)=p除q,则tanA除tanB=加油加油
sin(A+B)/sin(A-B)=(sinAcosB+cosAsinB)/(sinAcosB-cosAsinB)=p/q
tanA/tanB=sinAcosB/sinBcosA=[(sinAcosB+cosAsinB)+(sinAcosB-cosAsinB)]/[(sinAcosB+cosAsinB)-(sinAcosB-cosAsinB)]=(p+q)/(p-q)
似乎是合比性质.