y=1+e^(1/x)求dy

设y=e^(-x) cos 1/x,求dy. y=1+e^(1/x)求dy 求(x-e^-y)dy/dx=1通解 y=ln(1+e的X次方)　　求dy 已知函数y=e^x+1求微分dy. 设y=ln(1+e^-x)求dy 设y=e^1-2x sinx,求dy 设y=e∧1/x+sin2x,求dy 设y=e^cos^2*1/x,求dy 求dy/dx y=e^(2x+1) y=e^2x+x^2-yarcsin(1／x),求y′及dy y=e^-x^2,求dy 求函数y=1+xe^y在点（0,1）处的微分我的做法是：dy=d(1+x*e^y)dy=d(x)e^y+d(e^y)xdy=dx*e^y+e^y*dy*x dy(1-e^y*x)=dx*e^ye^ydy= ------------- * dx(1-e^y*x) 由方程y^2*sinx+e^y+2x=1,求dx/dy是dy/dx 打错了 y=1(2x+1) 求dy/dx是y=e^(2x+1) y=(x-1) * 立方根(x+2) / (x-3)^(2) * e^(2x) 求dy 求下列微分方程通解 (1+e^x/y)dx+e^x/y(1-x/y)dy=0 求微分方程的通解.[1+2e^(x/y)]dx+ 2e^(x/y)*[1-x/y]dy=0.