(2a-1)(a-4)-(a+3)(a-1)计算要详细的过程.

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/05 22:57:30
(2a-1)(a-4)-(a+3)(a-1)计算要详细的过程.(2a-1)(a-4)-(a+3)(a-1)计算要详细的过程.(2a-1)(a-4)-(a+3)(a-1)计算要详细的过程.(2a-1)(

(2a-1)(a-4)-(a+3)(a-1)计算要详细的过程.
(2a-1)(a-4)-(a+3)(a-1)计算
要详细的过程.

(2a-1)(a-4)-(a+3)(a-1)计算要详细的过程.
(2a-1)(a-4)-(a+3)(a-1)
= 2a^2-8a-a+4-a^2+a-3a+3
= a^2-11a+7
^2是平方的意思 .

(2a-1)(a-4)-(a+3)(a-1)
=(2a²-a-8a+4)-(a²+3a-a-3)
=2a²-a²-a-8a-3a+a+4+3
=a²-11a+7

(2a-1)(a-4)-(a+3)(a-1)
=(2a^2-8a-a+4)-(a^2-a+3a-3)
=2a^2-9a+4-a^2-2a+3
=a^2-11a+7

=2a^-8a-a+4-a^+a-3a+3
=a^-11a+7
注: ^为 平方

用十字交叉法
=2a*a-9a+4-a*a-2a+3=a*a-11a+7
a*a是a的平方