(a-1)(a-2)(a-3)(a-4)-3因式分解,
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(a-1)(a-2)(a-3)(a-4)-3因式分解,(a-1)(a-2)(a-3)(a-4)-3因式分解,(a-1)(a-2)(a-3)(a-4)-3因式分解,(a-1)(a-2)(a-3)(a-4
(a-1)(a-2)(a-3)(a-4)-3因式分解,
(a-1)(a-2)(a-3)(a-4)-3因式分解,
(a-1)(a-2)(a-3)(a-4)-3因式分解,
(a-1)(a-2)(a-3)(a-4)-3=(a²-5a+4)(a²-5a+6)-3
=(a²-5a)²+10(a²-5a)+24-3
=(a²-5a)²+10(a²-5a)+21
=(a²-5a+3)(a²-5a+7)
原式=[(a-1)(a-4)]×[(a-2)(a-3)]-3=(a²-5a+4)(a²-5a+6)-3=[(a²-5a+5)-1][(a²-5a+5)+1]-3=(a²-5a+5)²-1-3=(a²-5a+5+2)(a²-5a+5-2)=(a²-5a+7)(a²-5a+3).
(a-1)(a-2)(a-3)(a-4)-3=[(a-1)(a-4)][(a-2)(a-3)]
=[(a^2-5a)+4][(a^2-5a)+6]-3=(a^2-5a)^2+10(a^2-5a)+24-3
=(a^2-5a)^2+10(a^2-5a)++21=(a^2-5a+3)(a^2-5a+7)
a(a-1)(a-2)(a-3)(a-4)因式分解
【1】a+a=a×a a= [ ]【2】a×a=a÷a a=[ ]【3】a×a=a-a a=[ ] [4]a-a=a+a a=[ ]
a+a+1+a+2+a+3+a+4+a+5+a+6+a+7.+a+2013+a+2014=?
幂的计算题1、a×a^2×a^3×a^4×a^52、a+2a+3a+4a+a×a^2×a^3×a^4
[a^2-4/(a-3)(a+2)+(a+2)/a-3]除以a+1/a-3
(a+1/a方-a+4/1-a方)/a方+2a-3/a+3
(a 1)(a 2)(a 3)(a
(a+2)(a+1)-a(a-3)
a=-1 求a-2a+3a-4a+5a-6a+...+99a-100a
(a+4)(2a+1)(a-3)
(a-1)(a-2)(a-3)(a-4)-3因式分解,
因式分解:(1) a*4-a*3+a*2-a
因式分解:(a+1)(a+2)(a+3)(a+4)-120
(a+1)(a+2)(a+3)(a+4)的答案
2a*a+3a+2/a+1-a*a-a-5/a+2-3a*a-4a-5/a-2+2a*a-8a+5/a-3
化简后,求值:a×2a×3a×4a×5a×(a+2a+3a+4a+5a),其中a³=1/3
a+a^2+a^3+a^4+a^5+a^6...+a^n=a^n+1-a/a-1 (a-1)≠0
因式分解:a+2/a+1-a+3/a+2-a-4/a-36+a-5/a-4