已知数列{An}满足A(n+1)*2=An*2+4,且A1=1,An>0,求An通项公式?令Bn=An*2(n?N)则：Bn+1=Bn+4即：Bn+1-Bn=4又因为B1=A1*2=1 所以Bn=1+(n-1) *4=4n-3即：An=(4n-3)开根号(n?N)

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