1/9{1/7[1/5(2m-1/3-4)+6]+8}=1这方程怎么解我头晕了……2m-1/3是一体的!
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1/9{1/7[1/5(2m-1/3-4)+6]+8}=1这方程怎么解我头晕了……2m-1/3是一体的!1/9{1/7[1/5(2m-1/3-4)+6]+8}=1这方程怎么解我头晕了……2m-1/3是
1/9{1/7[1/5(2m-1/3-4)+6]+8}=1这方程怎么解我头晕了……2m-1/3是一体的!
1/9{1/7[1/5(2m-1/3-4)+6]+8}=1这方程怎么解我头晕了……
2m-1/3是一体的!
1/9{1/7[1/5(2m-1/3-4)+6]+8}=1这方程怎么解我头晕了……2m-1/3是一体的!
1/9{1/7[1/5(2m-1/3-4)+6]+8}=1
1/7[1/5(2m-1/3-4)+6]+8=9
1/7[1/5(2m-1/3-4)+6]=1
1/5(2m-1/3-4)+6=7
1/5(2m-1/3-4)=1
2m-1/3-4=5
2m-1/3=9
2m-1=27
2m=28
m=14
m=14
已知m>4,化简|m-4|+|7-2m|+|m×m-2m+1|-|m×m-2m-3|
计算(3m^2)^3-7m^3【m^3-m(4m^2+1)】等于 A.7m^3+9m^4 B.7m^4+48m^6 C.-7m^2+7m^4+31m^5 D.-7m^3-28m计算(3m^2)^3-7m^3【m^3-m(4m^2+1)】等于 A.7m^3+9m^4 B.7m^4+48m^6 C.-7m^2+7m^4+31m^5 D.-7m^3-28m^5-7m^6+27m^7 正确率一定要高!
当m=1/2时,求15m²-9-{-4m²+[5m-8m²-(2m²-m)+9m²]-3m}
计算:1/m(m+1)+1/(m+1)(m+2)+1/(m+2)(m+3)+1/(m+3)(m+4)+1/(m+4)(m+5)+.+1/(m+9)(m+10)
已知m>4,化简:|m-4|+|7-2m|+|m^2-2m+1|-|m^2-2m-3|
化简求值 m-4/m^2-9(1加上 14m-7/m^2+8m+16)÷1/m-3 其中m=5化简求值:(m-4)/(m^2-9)•{1+[(14m-7)/(m^2+8m+16)]}÷[1/(m-3) ]其中m=5
化简求值m-4/m^2-9(1加上 14m-7/m^2-8m+16)÷1/m-3 其中m=5化简求值m-4/m^2-9(1加上 14m-7/m^2-8m+16)÷1/m-3 其中m=5
有9条线段分别长1m,2m,3m,4m,5m,6m,7m,8m,9m;从中取出若干条,顺次连接,围成一个正方形,问有多少种取法
3(m+1)^2+4(m+1)(m-1)-7m(m-1)
通分1/2m^2+3m与(2m+5)/4m^2-9
[(m-3)/(m+5)]^2+[(4-2m)/(m+5)]^2=1,求m
1/m(m+1)+1/(m+1)(m+2)+1/(m+2)(m+3)+.+1/(m+9)(m+10)
若m为正整数,且m不能被4整除,试说明1^m+2^m+3^m+4^m+…+9^m一定是5的倍数
1/2m^2+3m-2/3-2m+2m-5/4m^2-9
m*m-5m-1=0则2m*m-5m+1/m*m
4m(m的平方-2m-1)+m(2m+5)(5-2m)
若多项式5x*x-2mxy-3y*y+4xy-3x+1中不含xy项,求(-(m*m*m)+2(m*m)-m+1)-(m*m*m+2m*m-m+4)
(M-1/M^2+6M+9)+(M-3/M^2+4M+3)怎么化简