lg^32+lg^35+3log2*log5求详细过程,谢谢
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lg^32+lg^35+3log2*log5求详细过程,谢谢lg^32+lg^35+3log2*log5求详细过程,谢谢lg^32+lg^35+3log2*log5求详细过程,谢谢lg³2+
lg^32+lg^35+3log2*log5求详细过程,谢谢
lg^32+lg^35+3log2*log5
求详细过程,谢谢
lg^32+lg^35+3log2*log5求详细过程,谢谢
lg³2+lg³5+3lg2lg5
=(lg2+lg5)[(lg2+lg5)²-3lg2lg5]+3lg2lg5
=lg10(lg²10-3lg2lg5)+3lg2lg5
=1-3lg2lg5+3lg2lg5
=1.
lg^32+lg^35+3log2*log5求详细过程,谢谢
Log2(4)*lg(5)+lg(x-1)=1+lg(2x+3) 第一个log2的2是下标Log2(4)*lg(5)+lg(x-1)=1+lg(2x+3)第一个log2的2是下标
计算(1)log327+ lg 1002+ log21 (2)lg 5+lg 2+ log2 18-log2 9 (3)ln e 3 +2 log2 6 (4) log8 9×log27 32
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1/2 * lg 32/7 - 4/3 * lg √8 +lg √35 知道的告诉下,
3lg 2 lg 5
若lg2,lg(2^x-1),lg(2^x+3)成等差数列,则x=A.32B.25C.log2 5D.0
为什么lg(log2 10)与lg(lg2)互为相反数
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计算log3(1/9)+lg(1/10)+log2(6)-log2(3)+5^[log5(3)]
0.5lg(32/49)—4/3lg√8+lg√245
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log2(32)-log2(3÷4)+log2log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2【log2(32)-log2(3÷4)+log2(6)】=?lgx+lg(x+15)=2 ..X
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