2log5(底)25-3log2(底)64求解 log2(底)(log2(底)32-log2(底)3/4+log2(底)6
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2log5(底)25-3log2(底)64求解log2(底)(log2(底)32-log2(底)3/4+log2(底)62log5(底)25-3log2(底)64求解log2(底)(log2(底)32
2log5(底)25-3log2(底)64求解 log2(底)(log2(底)32-log2(底)3/4+log2(底)6
2log5(底)25-3log2(底)64求解
log2(底)(log2(底)32-log2(底)3/4+log2(底)6
2log5(底)25-3log2(底)64求解 log2(底)(log2(底)32-log2(底)3/4+log2(底)6
2log5(底)25-3log2(底)64=2*2-3*6=4-18=-14
log2(底)(log2(底)32-log2(底)3/4+log2(底)6
=log2(底)5-log2(底)3+log2(底)4+log2(底)6
=log2(底)5+3
2log5(底)25-3log2(底)64求解 log2(底)(log2(底)32-log2(底)3/4+log2(底)6
lg(1/4)-lg2(5) 2log5(10)+log5(0.25) 2log2(25)-3log2(64) log2(log2(16) )
换底公式习题在线等2log5(25)-3log2(24)
2log5(25)+3log2(64)请使用换底公式解决
1.lg1/4-lg25=?2.2log5(底数)10+log5(底数)0.25=?3.2log5(底数)25-3log2(底数)64=?4.log2(底数)(log2(底)16)=?
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log2(32)-log2(3÷4)+log2log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2【log2(32)-log2(3÷4)+log2(6)】=?lgx+lg(x+15)=2 ..X
求(log2)^3+(log5)^3+log5×log8的值.(以10为底)
2^(1/2log2 3)+(1/25)^log5 3=
log3 25×log2 27×log5 2^-3=_____
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2log5^25–3log2^64等于?
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2log5 25+3log2 64等于多少
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