(2X+Y-Z+5)(2X-Y+Z+5)
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/26 20:25:23
(2X+Y-Z+5)(2X-Y+Z+5)(2X+Y-Z+5)(2X-Y+Z+5)(2X+Y-Z+5)(2X-Y+Z+5)原式=[(2X+5)+(Y-Z)][(2X+5)-(Y-Z)]=(2X+5)&#
(2X+Y-Z+5)(2X-Y+Z+5)
(2X+Y-Z+5)(2X-Y+Z+5)
(2X+Y-Z+5)(2X-Y+Z+5)
原式= [(2X+5)+(Y-Z)][(2X+5)-(Y-Z)]
=(2X+5)²-(Y-Z)²
=4X²+20X+25-Y²+2YZ-Z²
(2X+Y-Z+5)(2X-Y+Z+5)
=[(2x+5)+(y-z)][(2x+5)-(y-z)]
=(2x+5)²-(y-z)²
=4x²+10x+25-y²+2yz-z²
2(x+y-z)-3(x-y+z)-5(x+y-z)+6(x-y+z) 计算
x/2=y/3=z/5 x+3y-z/x-3y+z
1.(x+y-z)+(x-y+z)-(x-y-z) 2.2x-(3x-2y+3)-(5y-2)
因式分解:25x y^2 z^2 (x+y-z)-30xyz(z-x-y)^2+5x y z^3 (z-x-y)
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
(2x-3y+z)-3{x-2【-z+(x-y)】-(3y-5z)}
已知x+y-7z=0 x-2y+5z=0(xyz不等于0),求x+2y-z/y-2x+12z
已知2x+3y-4z=0,3x+4y+5z=0,求x+y+z/(除以)x-y+z的值.
已知x::y:z=3:4:5,(1)求x+y分之z的值;(2)若x+y+z=6,求x,y,z.
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
1.已知x:y:z=4:5:7,求:(一)2x+3y+z/5z; (二)x+y/y+z 非常急,
{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2
x+2y+3z=23 y-z=5 x+2z=10
(x-2y+z)(-x+2y+z)
x+2y-z)(x+2y-z)
(x+2y-z)(x-2y+z)
设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值
化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(x-2z+y)(y+z-2x)+(x-z)(y-z)/(y+z-2x)(x-2y+z)