x+2y+3z=23 y-z=5 x+2z=10
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x+2y+3z=23y-z=5x+2z=10x+2y+3z=23y-z=5x+2z=10x+2y+3z=23y-z=5x+2z=10用z把xy表示出来y=5+zx=10-2z所以式子变成10-2z+2
x+2y+3z=23 y-z=5 x+2z=10
x+2y+3z=23 y-z=5 x+2z=10
x+2y+3z=23 y-z=5 x+2z=10
用z把x y 表示出来
y=5+z
x=10-2z
所以式子变成10-2z+2(5+z)+3z=23
得出z=1
再把z=1带入y=5+z 和 x=10-2z
得出x=8 y=6 z=1
解，由第二三个方程：y=5+z，x=10-2z，代入：
10-2z+10+2z+3z=23
解得z=1，∴y=6，x=8
x/2=y/3=z/5 x+3y-z/x-3y+z
x+2y+3z=23 y-z=5 x+2z=10
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