把4.6g的纳慢慢地放进10g的水裏,当反应完成后,剩下的溶剂的总质量会是多少?另付上英文原题:4.6g of sodium are added slowly to 10g of water in a small dish.What is the total mass of the solution left when the reaction is
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把4.6g的纳慢慢地放进10g的水裏,当反应完成后,剩下的溶剂的总质量会是多少?另付上英文原题:4.6g of sodium are added slowly to 10g of water in a small dish.What is the total mass of the solution left when the reaction is
把4.6g的纳慢慢地放进10g的水裏,当反应完成后,剩下的溶剂的总质量会是多少?
另付上英文原题:
4.6g of sodium are added slowly to 10g of water in a small dish.What is the total mass of the solution left when the reaction is complete?
把4.6g的纳慢慢地放进10g的水裏,当反应完成后,剩下的溶剂的总质量会是多少?另付上英文原题:4.6g of sodium are added slowly to 10g of water in a small dish.What is the total mass of the solution left when the reaction is
因为4.6g Na与3.6g 水才能完全反应完
设:共有xg水被反应.
2Na+2H2o==2NaOH+H2
46 36
4.6 X
46/4.6=36/X
解得X=3.6
SO 溶剂H2O还剩10-3.6=6.4 g
溶剂就是水,所以还是10G
4.6克的钠是溶质 10克的水是溶剂 所以溶剂的总质量是10克
反映剩下的是氢氧化钠溶液
溶剂是水 应该是10g水减去反映消耗的的水3.6g 所以溶剂问6.4g
2Na+2H2O=2NaOH+H2
纳在水里发生如下反应2Na+2H2O=2NaOH+H2 根据方程4.6克Na消耗3.6克水,还有10-3.6=6.4克水作为NaOH溶液的溶剂。
2Na---2H2O---H2
反应消耗水3.6g
跑掉H20.2g
剩余为溶剂10-3.6-0.2=6.2g
2Na---2H2O---H2
反应消耗水3.6g
跑掉H20.2g
剩余为溶剂10-3.6-0.2=6.2g
因为4.6g Na与3.6g 水才能完全反应完
设:共有xg水被反应.
2Na+2H2o==2NaOH+H2
46 36
4.6 X
46/4.6=36/X
解得X=3.6
SO 溶剂H2O还剩10-3.6=6.4 g
同上,6.4克