M={(x,y)|y≥x^2},N={(x,y)|x^2+(y-a)^2≤1},则使M∩N=N成立的充要条件是答案a≥5/4

若[-3(x+y)^m*(x-y)^2n]^2*[-(x+y)^2]=-a(x+y)^10*(x-y)^12-n,求m,n的值 x^n*y*(-x^2y^m) 已知M=(x,y)|y>=x2 N=(x,y)|x2+(y-a)2 x+y=m,x-y=n,那么2x-3y等于 x+y=m,x-y=n,那么2x-3y等于多少 设X>0,y>0,M=(X+Y)/(2+X+Y),N=(X/2+X)+(Y/2+Y),则M,N的大小关系? 4x^(m+6)y^2+X^3y^n=单项式,m^n= 已知集合M={（x,y)|y=-x^2+2x},N={(x,y)|y=2x^2-4x},则M∩N=? X^3*y^(m-1)*x^(m+y)*y^(2n+2)=x^9y^9 已知M={(x,y)|y=-x^2+mx-1},N={(x,y)|y=-x+3,0 已知集合M={(x,y)|x^2+y^2=0},N={(x,y)||x|+|y| 集合N=｛（x,y)|（x-1）^2｝+(y-1)^20},M={(x,y)|x^2+y^2 假设集合U={(x,y)|x∈R,y∈R },A={(x,y)|2x-y+m>0},B={(x,y)|x+y-n 已知x^m+n=9,y^m+n=16,求（-三分之一*x^m*y^n)^2*x^2n*y^2n的值? 已知x^m+n=9,y^m+n=16,求（-三分之一*x^m*y^n)^2*x^2n*y^2n的值? 若不等式组x>m,x=2,y+n (x+y)(m+n)2-(x+y)(m+n)2 设集合M={y|y=x^2,x∈R}N={(x,y)|y=-x,x∈R}则M∩N=