设函数f(x)=√3sin(wx-π/3),且f(x)的周期为8,求f(x)的单调增区间

设函数f(x)=sin(wx+t)(-π/2 设函数f(x)=sin(wx+t)(-π/2 设函数f(x)=√3sin(wx-π/3),且f(x)的周期为8,求f(x)的单调增区间 已知函数f(x)=√3sin(wx+φ)-cos(wx+φ)(0 已知函数f(x)=√3 sin( wx+φ)-cos(wx+φ) (0 已知函数f(x)=√3 sin( wx+φ)-cos(wx+φ) (0 已知函数f(x)=√3sin(wx+φ)-cos(wx+φ)(0 函数f(x)=√3sin^(wx/2)+sin(wx/2)cos(wx/2) (w>0)的周期为π,求w的值和函数f(x)的单调递增区间 函数f(x)=3sin(wx+ φ)对任意实数x都有f(π/3+x)=f(π/3-x)恒成立,设g(x)=3cos(wx+ φ)+1,则g(π/3)=___. 已知函数f x=√3sin(wx+φ/2)*cos(wx+φ/2)+sin^2(wx+φ/2)(w>0,0 [非常急]已知函数f(x)=根号3sin(wx+φ)-cos(wx+φ)(0 已知函数f(x)=根号3sin(wx+φ)-cos(wx+φ)(0 已知函数f(x)=根号3sin(wx+a)-cos(wx+a)(0 已知函数f(x)=根号3sin(wx+φ)-cos(wx+φ)(0 已知函数f(x)=根号3sin(wx+fai)-cos(wx+fai)(0 设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ| 设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ| 设函数f(x)=sin(wx+φ)+cos(wx+φ)(w>0,|φ|