若x=(1-√5)/2,则√(1/x-1/x³)-³√(x^4-x²)的值为A 1/2 B 1 C √5/2 D√5
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/23 23:58:27
若x=(1-√5)/2,则√(1/x-1/x³)-³√(x^4-x²)的值为A1/2B1C√5/2D√5若x=(1-√5)/2,则√(1/x-1/x³)-
若x=(1-√5)/2,则√(1/x-1/x³)-³√(x^4-x²)的值为A 1/2 B 1 C √5/2 D√5
若x=(1-√5)/2,则√(1/x-1/x³)-³√(x^4-x²)的值为
A 1/2 B 1 C √5/2 D√5
若x=(1-√5)/2,则√(1/x-1/x³)-³√(x^4-x²)的值为A 1/2 B 1 C √5/2 D√5
x=(1-√5)/2 < 0
===> x^2 = (3-√5)/2
===> x^2-1 = x
因此:
√(1/x-1/x³)-³√(x^4-x²)
=√[ (x^2-1)/x³] - ³√ [ x^2(x^2-1) ]
=√[1/x^2] - ³√ [ x^3 ]
=-1/x-x
=(1+√5)/2 - (1-√5)/2
=√5
若x=√2,求代数式[(x^2-2x+4)/(√x^2-4x+4)]/[(x^3+8)/(x^2-4)]*[|6-x|/(x^2-5x-6)-[1/(x^2-x+1)]^-1的值
xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1
f(x,-x)=x^2+2x,fx(x,-x)=5x+1,则fy(x,-x)=
若2x-3y+4=0则x(x*x-1)+x(5-x*x)-6y+7
已知1/√(x)+√(x)=√5,求√(x/x2+x+1)+√(x/x2-x+1)的值定义域 x>0,两边平方,x+2+1/x=5,x+1/x=3,x^2-3x+1=0,x^2+x+1-4x=0,x^2+x+1=4x,x^2-x+1-2x=0.x^2-x+1=2x,√[x/(x^2+x+1)]-√[x/(x^2-x+1)]=√[x/(4x)]-√[x/2x]=√(1/4)-√(1/2)
若2X*X-5X+(8/2X*X-5X+1)-5=0,则2x*x-5x-1的值为多少
若X+1/X=2√3,则X-1/X=?
若x=√17-1,则x的5次方+2x⁴-17x³-x²+18x-16的值是多少
已知x*x-3x+1=0求√(x*x+1/x-2)=?
*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X ||
已知x=(3-√5)/2,则x^3-3x^2+3x+(6/(x^2+1))=?
若a^2x=√2 -1,则(a^3x+a^-3x)/(a^x+a^-x)等于?
设x=√3 -2,则x^6+3x^5+11x^3+2x+1=_____
填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x
已知X+1/X=√5,则X²+1/X²=(?),X-1/X=(?)
若x^2-5x+1=0,则x^2+x+1/x^2+1/x=
若√x-1-√1-x=(x+y)²先化简再求值:(1/2x)-(1/x+y)[x²-y²+(x+y/2x]
f(√x+1)=x+2√x,求f(x) 若f(1/x)=x/1-x,求f(x)