In the integer 3589 the digits are all different and increase from left to right.How many integers between 4000 and 5000 have digits that are all different and that increase from left to right?这是一道填空题,不理解题目意思,求地道翻

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Intheinteger3589thedigitsarealldifferentandincreasefromlefttoright.Howmanyintegersbetween4000and5000

In the integer 3589 the digits are all different and increase from left to right.How many integers between 4000 and 5000 have digits that are all different and that increase from left to right?这是一道填空题,不理解题目意思,求地道翻
In the integer 3589 the digits are all different and increase from left to right.How many integers between 4000 and 5000 have digits that are all different and that increase from left to right?
这是一道填空题,不理解题目意思,求地道翻译+解答
If the letters L,O,G,I,and C are randomly arranged to from a five-letter "word",what is the probability that the result will be the word LOGIC?
A 1/120 B 1/24 C 1/5 D 1/4 E 1/2
求用Cmn或Pmn的排列组合公式做,
Three fair coins are tossed at the same time.What is the probability that all three coins will come up heads?
A 1/8 B 1/6 C 1/4 D 1/3 E 3/8
求用Cmn或Pmn的排列组合公式做,
If I 6-5y I >20,which of the following is a possible value of
A -6 B -1 C 1 D 3 E -2
If g(x)>0 for all real values of x,which of the following could be the function
A g(x)=x + 1 B g(x)=x - 1 C g(x)=x^2 + 1 D g(x)=x^2 - 1 E g(x)x^3 + 1

In the integer 3589 the digits are all different and increase from left to right.How many integers between 4000 and 5000 have digits that are all different and that increase from left to right?这是一道填空题,不理解题目意思,求地道翻
第五题问你在x全体实数域上g(x)>0恒成立,所以只能选C
第四题是问你20

1 如果字母L.O.G.I.C随即组成一个五个字母的单词。那么诅咒logic单词的概率为。1/A55等于1/120
2三个平均的英语被同时抛弃。三个都是人头向上的概率为。1/(3*A22)等于1/8
3 如果6减5y的绝对值大于而是。下面那个是可能的y的值。代入可得A。。
4如果g(x)>0对全体实x满足。下面哪个可能是g(x)。选C。...

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1 如果字母L.O.G.I.C随即组成一个五个字母的单词。那么诅咒logic单词的概率为。1/A55等于1/120
2三个平均的英语被同时抛弃。三个都是人头向上的概率为。1/(3*A22)等于1/8
3 如果6减5y的绝对值大于而是。下面那个是可能的y的值。代入可得A。。
4如果g(x)>0对全体实x满足。下面哪个可能是g(x)。选C。

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  1. 3589这个数,数位从左到右递增,也就是说,9比8大比5大比3大。接下来您应该懂了。

  也就是求组合,就是求有多少种组合,从10个数字中选3个数字,且3个数字不同(因为第一位只可能是3,所以是选3个数,不是选4个数;还因为选完了数会自动排,所以是组合。)

答案 10C3

2. 排列。5个字母排列,所以是 1/...

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  1. 3589这个数,数位从左到右递增,也就是说,9比8大比5大比3大。接下来您应该懂了。

  也就是求组合,就是求有多少种组合,从10个数字中选3个数字,且3个数字不同(因为第一位只可能是3,所以是选3个数,不是选4个数;还因为选完了数会自动排,所以是组合。)

答案 10C3

2. 排列。5个字母排列,所以是 1/(5P5)=1/120

3. 是独立事件,不是排列组合(1/2)^3=1/8

4. 这种,要么是一个很小的数,要么是一个很大的数,-6的绝对值比3大,所以是-6

5. 哈哈,想一下函数图象,奇偶性,就知道是C了,实在不行用计算器画。

SAT2还是很容易的。

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