m^3-4m^2+16m+192=0
来源：学生作业帮助网 编辑：六六作业网 时间：2024/09/09 05:50:33
m^3-4m^2+16m+192=0m^3-4m^2+16m+192=0m^3-4m^2+16m+192=0m^3-4m^2+16m+192=0(m^3+4m^2)-(8m^2-16m-192)=0m
m^3-4m^2+16m+192=0
m^3-4m^2+16m+192=0
m^3-4m^2+16m+192=0
m^3-4m^2+16m+192=0
(m^3+4m^2)-(8m^2-16m-192)=0
m^2(m+4)-8(m^2-2m-24)=0
m^2(m+4)-8(m-6)(m+4)=0
(m+4)(m^2-8m+48)=0
(m+4)[(m-4)^2+32]=0
m=-4
m^3-4m^2+16m+192=0
(m+4)(m^2-8m+48)=0
所以m+4=0或m^2-8m+48=0
当m+4=0时，m=-4
当m^2-8m+48=0时，b^2-4ac=64-4*48=-128<0(无解)
所以m=-4
m^3-4m^2+16m+192=0
(m+3m+5m+...+2015m)-(2m+4m+6m+...+2014m)=
m-2m-3m+4m-5m-6m+7m.2004m=?
(m+3m+5m.+2013m)-(2m+4m+6m+.+2012m)=?
(m+3m+5m+7m+.+2009m)-(2m-4m-6m-.-2008m)=?
已知m-1/m=3,m不等于0,求m^2-1/m^2,m^3-1/m^3,m^4-1/m^4
已知m^2+m-1=0,那么m^4+2m^3-m-2009=
因式分解-4m^3-16m^2-2m=
计算(m+3m+5m……+2009m)—(2m+4m+6m+2008m)=
计算：（m+3m+5m+…+2015m）-(2m+4m+6m+…+2014m)=
计算（m+3m+5m+.+2009m)-(2m+4m+6m+.+2010m)=多少
(m+3m+5m+...+2011m)-(2m+4m+6m+...+2012m)=多少
计算：(m+3m+5m+…+2011m)-(2m+4m+6m+…+2010m)=
(m+3m+5m+...+2011m)-(2m+4m+6m+...+2012m)=多少
计算(m+3m+5m+...+2011m)-(2m+4m+6m+...+2010m)=
若方程(2m.m+m-3)x+(m.m-m)y-4m+1=0表示一条直线.则实数m满足
已知m*m+m-1=0,求m*m*m+2m*m-2005
m*m-5m-1=0则2m*m-5m+1/m*m