化简 [a(x+2)チ0ナ5+b(x+2)+1]-(axチ0ナ5+bx+1)=x
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化简[a(x+2)チ0ナ5+b(x+2)+1]-(axチ0ナ5+bx+1)=x化简[a(x+2)チ0ナ5+b(x+2
化简 [a(x+2)チ0ナ5+b(x+2)+1]-(axチ0ナ5+bx+1)=x
化简 [a(x+2)チ0ナ5+b(x+2)+1]-(axチ0ナ5+bx+1)=x
化简 [a(x+2)チ0ナ5+b(x+2)+1]-(axチ0ナ5+bx+1)=x
a(x平方+4x+4)+bx+2b+1-ax平方-bx-1=x
4ax+4a+2b=x
(4a-1)x=-(4a+2b)
x=(4a+2b)/(1-4a)