0,+1/2,+0,+1/4,+0,+1/6+求出极限+an=?

8 0 0 0 3 0 0 0 0 0 0 3 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 7 0 5 0 0 6 0 0 1 0 0 0 4 9 0 0 0 5 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 7 0 9 0 0 5 0 0 2 4 0 8 0 0 0 0 0 线性方程组,矩阵-1 4 1 0 4 0 0 4 2 0 3 1 怎么化简算到 -1 4 1 0 -1 1 0 0 1 0 0 0 线性代数关于矩阵的问题?1 0 0 0 0 0 1 0 0 0 0 0 1 2 1 2 1 2 0 1 0 0 0 0 0 1 0 0 0 0 1 2 1 2 1 2 1 2 1 2 1 2 0 0 1 0 0 0 0 0 1 0 0 01 2 1 2 1 2 0 0 0 1 0 0 0 0 0 1 0 00 0 0 0 1 0 1 2 1 2 1 2 0 0 0 0 1 0 0 0 0 0 0 1 1 2 1 2 1 2 0 0 0 0 0 1 1 求四阶行列式1 0 0 2,0 1 2 0,0 3 4 0,3 0 0 4的值 解矩阵方程（0 1 0,1 0 0,0 0 1)X(1 0 0,0 0 1,0 1 0)=(1 -4 3,2 0 -1,1 -2 0) matlab这个矩阵输不对啊,Error using vertcat CAT arguments dimensions are not consistent.A=[-4 1 0 1 0 0 0 0 01 -4 1 0 1 0 0 0 00 2 -4.67 0 0 1 0 0 01 0 0 -4 1 0 1 0 00 1 0 1 -4 1 0 1 00 0 1 0 2 -4.67 1 00 0 0 2 0 0 -4.67 1 00 0 0 0 2 0 1 -4.67 求矩阵(-3,4,0,0;4,3,0,0;0,0,-1,1;0,0,-3,2)的行列式 计算行列式|5 -2 0 0 0| 4 -1 0 0 0| 0 0 2 6 5| 0 0 1 3 5| 0 0 -2 7 9| 2道数独题目,在线等,急7 4 0 0 6 5 0 1 09 0 0 0 0 0 0 6 00 0 3 9 0 4 0 0 02 0 0 0 0 0 0 4 06 0 4 0 0 0 1 0 70 9 0 0 0 0 0 0 30 0 0 3 0 5 6 0 00 1 0 0 0 0 0 0 80 7 0 0 2 8 0 5 10 0 0 0 3 0 0 7 43 0 0 0 0 0 5 9 00 0 0 8 0 9 0 0 20 7 0 5 0 0 9 分块矩阵A是怎么转化为分块矩阵B的?C= 1 0 -1 1 D= 1 0 0 E= 1 0 0 0 F= 1 0 0 0 G= 1 0 0 H= 1 0 1 -10 2 2 2 0 1 0 0 1 0 0 0 1 0 0 0 0.5 0 0 1 -1 -1-1 4 5 3 0 0 1 0 0 1 0 0 0 0 0 1 -2 1 0 0 1 00 0 0 1 0 0 0 1A= | C D | B= | F G || E 0 | | H 设矩阵A={(0,1,0)(2,0,-1)(3,4,1)}.1={(1,0,0)(0,1,0)(0,0,1)}.求(1+A)-1设矩阵A={(0,1,0)(2,0,-1)(3,4,1)}.1={(1,0,0)(0,1,0)(0,0,1)}.求(1+A)^-1 下面这个矩阵变换如何计算a=[0,0,0,0,1,0,0,0,0,0,0,1,0,0,0,1,0,0,0,1,0,0,0,0];变换为：b=[0,0,0,0,0,1,2,3,4,5,6,0,1,2,3,0,1,2,3,0,1,2,3,4];开始出4个0不变,之后遇到1变为0,两个1之间的数依次加1,请问matlab如何实现. 用矩阵的初等变换求解矩阵方程{0 1 0}X{1 0 0}={1 -4 3} 求矩阵X 1 0 0 0 0 1 2 0 -10 0 1 0 1 0 1 -2 0 81方格如何填写0 0 4 0 9 0 8 0 0 0 3 0 5 0 0 0 0 4 0 9 5 4 0 0 3 0 0 7 0 0 2 0 0 0 8 1 4 8 0 0 5 0 0 0 0 0 0 6 1 0 0 0 0 0 5 0 0 0 2 7 1 0 0 1 0 8 0 0 0 0 0 6 0 6 0 0 0 0 9 0 0 请在“0”处填写1-9数字让小的九方格和大的九方格 猜测通项公式-1/2,0,-1/4,0,-1/6,0,-1/8,0 | 4 1 2 4 | | 1 2 0 2 || 10 5 2 0 || 0 1 1 7 | 英语翻译#include int map[9][9]={0,0,3,8,1,0,0,0,9,5,0,0,4,0,0,0,8,0,0,6,0,9,0,0,1,0,0,0,0,8,0,3,0,0,0,6,0,0,0,0,0,0,0,0,0,9,0,0,6,0,0,5,0,0,0,0,6,0,0,9,0,1,0,0,1,0,0,0,5,0,0,4,2,0,0,0,4,8,7,0,0}; void display() { int i; int j; for(i=0;i 计算五阶行列式 4 8 6 0 91 -1 3 0 2 0 4 1 -2 35 -3 0 0 0 2 0 0 0 0