7^(lg20)x(0.5)^(lg0.7)=感激不尽

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7^(lg20)x(0.5)^(lg0.7)=感激不尽7^(lg20)x(0.5)^(lg0.7)=感激不尽7^(lg20)x(0.5)^(lg0.7)=感激不尽7^(lg20)x(0.5)^(lg0

7^(lg20)x(0.5)^(lg0.7)=感激不尽
7^(lg20)x(0.5)^(lg0.7)=
感激不尽

7^(lg20)x(0.5)^(lg0.7)=感激不尽
7^(lg20)x(0.5)^(lg0.7)
=(10^lg7)^lg20 *(10^lg0.5)^lg0.7
=10^(lg7*lg20+lg0.5*lg0.7)
=10^[lg7*(1+lg2)+(lg5-1)*(lg7-1)]
=10^(lg7*lg2+lg7*lg5-lg5+1)
=10^(lg7-lg5+1)
=10^(lg7+lg2)
=10^lg14
=14

答案是14
用计算机啊